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213121211013000 = 233253103631364349
BaseRepresentation
bin110000011101010100100110…
…000100111001011110001000
31000221121012002122001000212200
4300131110212010321132020
5210413234220004404000
62033134311022440200
762614333166565603
oct6035244604713610
91027535078030780
10213121211013000
11619a821a616154
121baa039a433060
1391bc322cb07a4
143a8b19bb4b33a
151998b89b90500
hexc1d526139788

213121211013000 has 384 divisors, whose sum is σ = 728498062656000. Its totient is φ = 56191205952000.

The previous prime is 213121211012971. The next prime is 213121211013041. The reversal of 213121211013000 is 310112121312.

213121211013000 is a `hidden beast` number, since 2 + 131 + 21 + 211 + 0 + 1 + 300 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 584754826 + ... + 585119174.

It is an arithmetic number, because the mean of its divisors is an integer number (1897130371500).

Almost surely, 2213121211013000 is an apocalyptic number.

213121211013000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 213121211013000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (364249031328000).

213121211013000 is an abundant number, since it is smaller than the sum of its proper divisors (515376851643000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

213121211013000 is a wasteful number, since it uses less digits than its factorization.

213121211013000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 365110 (or 365093 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 213121211013000 its reverse (310112121312), we get a palindrome (213431323134312).

The spelling of 213121211013000 in words is "two hundred thirteen trillion, one hundred twenty-one billion, two hundred eleven million, thirteen thousand".