Base | Representation |
---|---|
bin | 11111000000110110110… |
… | …100001101011011111101 |
3 | 21112202001121220000220111 |
4 | 133000312310031123331 |
5 | 234404221144410010 |
6 | 4311023122350021 |
7 | 306655463204230 |
oct | 37006664153375 |
9 | 7482047800814 |
10 | 2131223435005 |
11 | 751935082825 |
12 | 2a50664bb311 |
13 | 125c86a47132 |
14 | 7521a629417 |
15 | 3a68845a58a |
hex | 1f036d0d6fd |
2131223435005 has 16 divisors (see below), whose sum is σ = 2923305793920. Its totient is φ = 1461167813952.
The previous prime is 2131223434999. The next prime is 2131223435041. The reversal of 2131223435005 is 5005343221312.
It is not a de Polignac number, because 2131223435005 - 233 = 2122633500413 is a prime.
It is a super-2 number, since 2×21312234350052 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4838919 + ... + 5260948.
It is an arithmetic number, because the mean of its divisors is an integer number (182706612120).
Almost surely, 22131223435005 is an apocalyptic number.
It is an amenable number.
2131223435005 is a deficient number, since it is larger than the sum of its proper divisors (792082358915).
2131223435005 is a wasteful number, since it uses less digits than its factorization.
2131223435005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10105908.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 2131223435005 its reverse (5005343221312), we get a palindrome (7136566656317).
The spelling of 2131223435005 in words is "two trillion, one hundred thirty-one billion, two hundred twenty-three million, four hundred thirty-five thousand, five".
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