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213130020223 = 223955740001
BaseRepresentation
bin1100011001111110001…
…0100000010101111111
3202101010101201211011201
43012133202200111333
511442442241121343
6241524404000331
721253363165231
oct3063742402577
9671111654151
10213130020223
118242a38178a
12353809900a7
1317137615903
14a45bc14251
15582600a94d
hex319f8a057f

213130020223 has 4 divisors (see below), whose sum is σ = 214085760448. Its totient is φ = 212174280000.

The previous prime is 213130020209. The next prime is 213130020277. The reversal of 213130020223 is 322020031312.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 213130020223 - 229 = 212593149311 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 213130020223.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (213130020923) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 477869778 + ... + 477870223.

It is an arithmetic number, because the mean of its divisors is an integer number (53521440112).

Almost surely, 2213130020223 is an apocalyptic number.

213130020223 is a deficient number, since it is larger than the sum of its proper divisors (955740225).

213130020223 is an equidigital number, since it uses as much as digits as its factorization.

213130020223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 955740224.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 213130020223 its reverse (322020031312), we get a palindrome (535150051535).

The spelling of 213130020223 in words is "two hundred thirteen billion, one hundred thirty million, twenty thousand, two hundred twenty-three".

Divisors: 1 223 955740001 213130020223