Base | Representation |
---|---|
bin | 11111000000111011100… |
… | …101101011000000100011 |
3 | 21112202021012120021012221 |
4 | 133000323211223000203 |
5 | 234404402144310201 |
6 | 4311035102531511 |
7 | 306660454632202 |
oct | 37007345530043 |
9 | 7482235507187 |
10 | 2131303510051 |
11 | 7519762a5351 |
12 | 2a5089296b97 |
13 | 125c9a502711 |
14 | 75227111239 |
15 | 3a6904c64a1 |
hex | 1f03b96b023 |
2131303510051 has 16 divisors (see below), whose sum is σ = 2172885510240. Its totient is φ = 2090129708800.
The previous prime is 2131303510027. The next prime is 2131303510057. The reversal of 2131303510051 is 1500153031312.
It is a cyclic number.
It is not a de Polignac number, because 2131303510051 - 29 = 2131303509539 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2131303509998 and 2131303510025.
It is not an unprimeable number, because it can be changed into a prime (2131303510057) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 84465705 + ... + 84490933.
It is an arithmetic number, because the mean of its divisors is an integer number (135805344390).
Almost surely, 22131303510051 is an apocalyptic number.
2131303510051 is a deficient number, since it is larger than the sum of its proper divisors (41582000189).
2131303510051 is a wasteful number, since it uses less digits than its factorization.
2131303510051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33254.
The product of its (nonzero) digits is 1350, while the sum is 25.
Adding to 2131303510051 its reverse (1500153031312), we get a palindrome (3631456541363).
The spelling of 2131303510051 in words is "two trillion, one hundred thirty-one billion, three hundred three million, five hundred ten thousand, fifty-one".
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