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213131124101 = 730447303443
BaseRepresentation
bin1100011001111110011…
…0101101110110000101
3202101010110210220102002
43012133212231312011
511442443031432401
6241524443355045
721253405443440
oct3063746556605
9671113726362
10213131124101
118242aa66085
1235381222a85
13171379111ac
14a45c020657
155826177a6b
hex319f9add85

213131124101 has 4 divisors (see below), whose sum is σ = 243578427552. Its totient is φ = 182683820652.

The previous prime is 213131124097. The next prime is 213131124139. The reversal of 213131124101 is 101421131312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 213131124101 - 22 = 213131124097 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (213131124181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15223651715 + ... + 15223651728.

It is an arithmetic number, because the mean of its divisors is an integer number (60894606888).

Almost surely, 2213131124101 is an apocalyptic number.

It is an amenable number.

213131124101 is a deficient number, since it is larger than the sum of its proper divisors (30447303451).

213131124101 is an equidigital number, since it uses as much as digits as its factorization.

213131124101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30447303450.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 213131124101 its reverse (101421131312), we get a palindrome (314552255413).

The spelling of 213131124101 in words is "two hundred thirteen billion, one hundred thirty-one million, one hundred twenty-four thousand, one hundred one".

Divisors: 1 7 30447303443 213131124101