Base | Representation |
---|---|
bin | 10011110110010111… |
… | …000100110101011001 |
3 | 2001000100101100020121 |
4 | 103312113010311121 |
5 | 322122124112213 |
6 | 13442513553241 |
7 | 1353105321643 |
oct | 236627046531 |
9 | 61010340217 |
10 | 21313113433 |
11 | 9047773637 |
12 | 4169875821 |
13 | 2018754631 |
14 | 106285b893 |
15 | 84b19b88d |
hex | 4f65c4d59 |
21313113433 has 8 divisors (see below), whose sum is σ = 21369941280. Its totient is φ = 21256341120.
The previous prime is 21313113431. The next prime is 21313113439. The reversal of 21313113433 is 33431131312.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 21313113433 - 21 = 21313113431 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 21313113398 and 21313113407.
It is not an unprimeable number, because it can be changed into a prime (21313113431) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 820438 + ... + 846016.
It is an arithmetic number, because the mean of its divisors is an integer number (2671242660).
Almost surely, 221313113433 is an apocalyptic number.
It is an amenable number.
21313113433 is a deficient number, since it is larger than the sum of its proper divisors (56827847).
21313113433 is a wasteful number, since it uses less digits than its factorization.
21313113433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 27767.
The product of its digits is 1944, while the sum is 25.
Adding to 21313113433 its reverse (33431131312), we get a palindrome (54744244745).
The spelling of 21313113433 in words is "twenty-one billion, three hundred thirteen million, one hundred thirteen thousand, four hundred thirty-three".
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