213131213102333 has 4 divisors (see below), whose sum is σ = 216625167415548. Its totient is φ = 209637258789120.

The previous prime is 213131213102321. The next prime is 213131213102341. The reversal of 213131213102333 is 333201312131312.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 90196294991929 + 122934918110404 = 9497173^2 + 11087602^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-213131213102333 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 213131213102296 and 213131213102305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (213131213102033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1746977156516 + ... + 1746977156637.

It is an arithmetic number, because the mean of its divisors is an integer number (54156291853887).

Almost surely, 2^{213131213102333} is an apocalyptic number.

It is an amenable number.

213131213102333 is a deficient number, since it is larger than the sum of its proper divisors (3493954313215).

213131213102333 is an equidigital number, since it uses as much as digits as its factorization.

213131213102333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3493954313214.

The product of its (nonzero) digits is 5832, while the sum is 29.

Adding to 213131213102333 its reverse (333201312131312), we get a palindrome (546332525233645).

The spelling of 213131213102333 in words is "two hundred thirteen trillion, one hundred thirty-one billion, two hundred thirteen million, one hundred two thousand, three hundred thirty-three".