Base | Representation |
---|---|
bin | 11111000001001001111… |
… | …000000010000011000011 |
3 | 21112202212220120222112220 |
4 | 133001021320002003003 |
5 | 234410400030012120 |
6 | 4311114544222123 |
7 | 306666425201400 |
oct | 37011170020303 |
9 | 7482786528486 |
10 | 2131543204035 |
11 | 751a89629a53 |
12 | 2a513560a943 |
13 | 12600807718b |
14 | 7524aca72a7 |
15 | 3a6a6571b40 |
hex | 1f049e020c3 |
2131543204035 has 192 divisors, whose sum is σ = 4341303195264. Its totient is φ = 886790553600.
The previous prime is 2131543204031. The next prime is 2131543204061. The reversal of 2131543204035 is 5304023451312.
It is not a de Polignac number, because 2131543204035 - 22 = 2131543204031 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2131543203987 and 2131543204005.
It is not an unprimeable number, because it can be changed into a prime (2131543204031) by changing a digit.
It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 57870925 + ... + 57907745.
It is an arithmetic number, because the mean of its divisors is an integer number (22610954142).
Almost surely, 22131543204035 is an apocalyptic number.
2131543204035 is an abundant number, since it is smaller than the sum of its proper divisors (2209759991229).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2131543204035 is a wasteful number, since it uses less digits than its factorization.
2131543204035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 37014 (or 37007 counting only the distinct ones).
The product of its (nonzero) digits is 43200, while the sum is 33.
Adding to 2131543204035 its reverse (5304023451312), we get a palindrome (7435566655347).
The spelling of 2131543204035 in words is "two trillion, one hundred thirty-one billion, five hundred forty-three million, two hundred four thousand, thirty-five".
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