Base | Representation |
---|---|
bin | 100110100101111000001… |
… | …1011110000011010110000 |
3 | 200210001121111212122202120 |
4 | 1031023300123300122300 |
5 | 1143400120000420222 |
6 | 15140345034114240 |
7 | 1055126434313325 |
oct | 115136033603260 |
9 | 20701544778676 |
10 | 5304023451312 |
11 | 1765472a65333 |
12 | 717b5687b980 |
13 | 2c62236358a1 |
14 | 144a04dc4b4c |
15 | 92e8323915c |
hex | 4d2f06f06b0 |
5304023451312 has 40 divisors (see below), whose sum is σ = 13702266425904. Its totient is φ = 1767981256704.
The previous prime is 5304023451283. The next prime is 5304023451329. The reversal of 5304023451312 is 2131543204035.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2539428 + ... + 4129980.
Almost surely, 25304023451312 is an apocalyptic number.
It is an amenable number.
5304023451312 is an abundant number, since it is smaller than the sum of its proper divisors (8398242974592).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5304023451312 is a wasteful number, since it uses less digits than its factorization.
5304023451312 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1660037 (or 1660031 counting only the distinct ones).
The product of its (nonzero) digits is 43200, while the sum is 33.
Adding to 5304023451312 its reverse (2131543204035), we get a palindrome (7435566655347).
The spelling of 5304023451312 in words is "five trillion, three hundred four billion, twenty-three million, four hundred fifty-one thousand, three hundred twelve".
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