Base | Representation |
---|---|
bin | 1001101100011111110100… |
… | …01100001111001111011010 |
3 | 2210111011221211112010120001 |
4 | 10312033322030033033122 |
5 | 10243302101232432302 |
6 | 113202154503323214 |
7 | 4330220311423033 |
oct | 466177214171732 |
9 | 83434854463501 |
10 | 21320120202202 |
11 | 687a8a3048a08 |
12 | 2483b9515050a |
13 | bb862b950a63 |
14 | 539c83a5ba8a |
15 | 26e8ba36c787 |
hex | 1363fa30f3da |
21320120202202 has 4 divisors (see below), whose sum is σ = 31980180303306. Its totient is φ = 10660060101100.
The previous prime is 21320120202193. The next prime is 21320120202223. The reversal of 21320120202202 is 20220202102312.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 19586634611041 + 1733485591161 = 4425679^2 + 1316619^2 .
It is a super-3 number, since 3×213201202022023 (a number of 41 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 21320120202202.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5330030050549 + ... + 5330030050552.
Almost surely, 221320120202202 is an apocalyptic number.
21320120202202 is a deficient number, since it is larger than the sum of its proper divisors (10660060101104).
21320120202202 is a wasteful number, since it uses less digits than its factorization.
21320120202202 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10660060101103.
The product of its (nonzero) digits is 384, while the sum is 19.
Adding to 21320120202202 its reverse (20220202102312), we get a palindrome (41540322304514).
The spelling of 21320120202202 in words is "twenty-one trillion, three hundred twenty billion, one hundred twenty million, two hundred two thousand, two hundred two".
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