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2132043314141 = 13164003331857
BaseRepresentation
bin11111000001100111101…
…011110011001111011101
321112211011202122012122102
4133001213223303033131
5234412411042023031
64311240331254445
7310015010104346
oct37014753631735
97484152565572
102132043314141
11752215961094
122a5254baa425
1312608786a410
147529748b0cd
153a6d540c7cb
hex1f067af33dd

2132043314141 has 4 divisors (see below), whose sum is σ = 2296046646012. Its totient is φ = 1968039982272.

The previous prime is 2132043314129. The next prime is 2132043314143. The reversal of 2132043314141 is 1414133402312.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 588858251641 + 1543185062500 = 767371^2 + 1242250^2 .

It is not a de Polignac number, because 2132043314141 - 210 = 2132043313117 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2132043314143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 82001665916 + ... + 82001665941.

It is an arithmetic number, because the mean of its divisors is an integer number (574011661503).

Almost surely, 22132043314141 is an apocalyptic number.

It is an amenable number.

2132043314141 is a deficient number, since it is larger than the sum of its proper divisors (164003331871).

2132043314141 is a wasteful number, since it uses less digits than its factorization.

2132043314141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 164003331870.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 2132043314141 its reverse (1414133402312), we get a palindrome (3546176716453).

The spelling of 2132043314141 in words is "two trillion, one hundred thirty-two billion, forty-three million, three hundred fourteen thousand, one hundred forty-one".

Divisors: 1 13 164003331857 2132043314141