Base | Representation |
---|---|
bin | 11111000001110001000… |
… | …110001001000101100111 |
3 | 21112211120202202100221212 |
4 | 133001301012021011213 |
5 | 234413222002324221 |
6 | 4311304131502035 |
7 | 310021635166610 |
oct | 37016106110547 |
9 | 7484522670855 |
10 | 2132201214311 |
11 | 752296aa98a3 |
12 | 2a5299a5791b |
13 | 1260b14a417c |
14 | 752b0430c07 |
15 | 3a6e41ecb5b |
hex | 1f071189167 |
2132201214311 has 4 divisors (see below), whose sum is σ = 2436801387792. Its totient is φ = 1827601040832.
The previous prime is 2132201214271. The next prime is 2132201214343. The reversal of 2132201214311 is 1134121022312.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 2132201214311 - 210 = 2132201213287 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2132201214361) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 152300086730 + ... + 152300086743.
It is an arithmetic number, because the mean of its divisors is an integer number (609200346948).
Almost surely, 22132201214311 is an apocalyptic number.
2132201214311 is a deficient number, since it is larger than the sum of its proper divisors (304600173481).
2132201214311 is an equidigital number, since it uses as much as digits as its factorization.
2132201214311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 304600173480.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 2132201214311 its reverse (1134121022312), we get a palindrome (3266322236623).
The spelling of 2132201214311 in words is "two trillion, one hundred thirty-two billion, two hundred one million, two hundred fourteen thousand, three hundred eleven".
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