Base | Representation |
---|---|
bin | 1001101100100011011010… |
… | …10101100001000111000111 |
3 | 2210111100221110120100212222 |
4 | 10312101231111201013013 |
5 | 10243320030303431120 |
6 | 113203114313002555 |
7 | 4330316216516666 |
oct | 466215525410707 |
9 | 83440843510788 |
10 | 21322052014535 |
11 | 68806a4552128 |
12 | 24844340b345b |
13 | bb8878c4248c |
14 | 539dc8446ddd |
15 | 26e97ec61525 |
hex | 13646d5611c7 |
21322052014535 has 16 divisors (see below), whose sum is σ = 27114333603840. Its totient is φ = 16067753237760.
The previous prime is 21322052014517. The next prime is 21322052014579. The reversal of 21322052014535 is 53541025022312.
It is not a de Polignac number, because 21322052014535 - 214 = 21322051998151 is a prime.
It is a super-2 number, since 2×213220520145352 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 21322052014495 and 21322052014504.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1793270087 + ... + 1793281976.
It is an arithmetic number, because the mean of its divisors is an integer number (1694645850240).
Almost surely, 221322052014535 is an apocalyptic number.
21322052014535 is a deficient number, since it is larger than the sum of its proper divisors (5792281589305).
21322052014535 is a wasteful number, since it uses less digits than its factorization.
21322052014535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3586552138.
The product of its (nonzero) digits is 72000, while the sum is 35.
Adding to 21322052014535 its reverse (53541025022312), we get a palindrome (74863077036847).
The spelling of 21322052014535 in words is "twenty-one trillion, three hundred twenty-two billion, fifty-two million, fourteen thousand, five hundred thirty-five".
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