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2132302002433 = 41283698326317
BaseRepresentation
bin11111000001110111000…
…110100111100100000001
321112211211210101221021021
4133001313012213210001
5234413423303034213
64311322132025441
7310024300653541
oct37016706474401
97484753357237
102132302002433
11752338989469
122a5307762281
131260c9332605
14752bd989321
153a6eceaad8d
hex1f0771a7901

2132302002433 has 16 divisors (see below), whose sum is σ = 2192424990336. Its totient is φ = 2072568159360.

The previous prime is 2132302002431. The next prime is 2132302002437. The reversal of 2132302002433 is 3342002032312.

It is a cyclic number.

It is not a de Polignac number, because 2132302002433 - 21 = 2132302002431 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2132302002398 and 2132302002407.

It is not an unprimeable number, because it can be changed into a prime (2132302002431) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 81010591 + ... + 81036907.

It is an arithmetic number, because the mean of its divisors is an integer number (137026561896).

Almost surely, 22132302002433 is an apocalyptic number.

It is an amenable number.

2132302002433 is a deficient number, since it is larger than the sum of its proper divisors (60122987903).

2132302002433 is a wasteful number, since it uses less digits than its factorization.

2132302002433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33624.

The product of its (nonzero) digits is 5184, while the sum is 25.

Adding to 2132302002433 its reverse (3342002032312), we get a palindrome (5474304034745).

The spelling of 2132302002433 in words is "two trillion, one hundred thirty-two billion, three hundred two million, two thousand, four hundred thirty-three".

Divisors: 1 41 283 6983 11603 26317 286303 1078997 1976189 7447711 81023749 183771611 305356151 7534636051 52007365913 2132302002433