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2132312544103 = 7304616077729
BaseRepresentation
bin11111000001110111101…
…110110101001101100111
321112211212112020111201111
4133001313232311031213
5234413434002402403
64311323150005451
7310024456400350
oct37016756651547
97484775214644
102132312544103
11752343929595
122a530b1a6887
131260cb5838a1
14752c1130d27
153a6edd8e56d
hex1f077bb5367

2132312544103 has 4 divisors (see below), whose sum is σ = 2436928621840. Its totient is φ = 1827696466368.

The previous prime is 2132312544091. The next prime is 2132312544139. The reversal of 2132312544103 is 3014452132312.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2132312544103 - 25 = 2132312544071 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2132312544143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 152308038858 + ... + 152308038871.

It is an arithmetic number, because the mean of its divisors is an integer number (609232155460).

Almost surely, 22132312544103 is an apocalyptic number.

2132312544103 is a deficient number, since it is larger than the sum of its proper divisors (304616077737).

2132312544103 is an equidigital number, since it uses as much as digits as its factorization.

2132312544103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 304616077736.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 2132312544103 its reverse (3014452132312), we get a palindrome (5146764676415).

The spelling of 2132312544103 in words is "two trillion, one hundred thirty-two billion, three hundred twelve million, five hundred forty-four thousand, one hundred three".

Divisors: 1 7 304616077729 2132312544103