Base | Representation |
---|---|
bin | 11111000001110111101… |
… | …110110101001101110011 |
3 | 21112211212112020111201221 |
4 | 133001313232311031303 |
5 | 234413434002402430 |
6 | 4311323150005511 |
7 | 310024456400365 |
oct | 37016756651563 |
9 | 7484775214657 |
10 | 2132312544115 |
11 | 7523439295a6 |
12 | 2a530b1a6897 |
13 | 1260cb5838b0 |
14 | 752c1130d35 |
15 | 3a6edd8e57a |
hex | 1f077bb5373 |
2132312544115 has 16 divisors (see below), whose sum is σ = 2755661848128. Its totient is φ = 1574597690496.
The previous prime is 2132312544091. The next prime is 2132312544139. The reversal of 2132312544115 is 5114452132312.
It is an interprime number because it is at equal distance from previous prime (2132312544091) and next prime (2132312544139).
It is a cyclic number.
It is not a de Polignac number, because 2132312544115 - 227 = 2132178326387 is a prime.
It is a super-2 number, since 2×21323125441152 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3020677 + ... + 3659113.
It is an arithmetic number, because the mean of its divisors is an integer number (172228865508).
Almost surely, 22132312544115 is an apocalyptic number.
2132312544115 is a deficient number, since it is larger than the sum of its proper divisors (623349304013).
2132312544115 is a wasteful number, since it uses less digits than its factorization.
2132312544115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 689838.
The product of its digits is 28800, while the sum is 34.
Adding to 2132312544115 its reverse (5114452132312), we get a palindrome (7246764676427).
The spelling of 2132312544115 in words is "two trillion, one hundred thirty-two billion, three hundred twelve million, five hundred forty-four thousand, one hundred fifteen".
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