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213250113535 = 5302314108509
BaseRepresentation
bin1100011010011010110…
…0100111111111111111
3202101102202201012020011
43012212230213333333
511443214012113120
6241544334004051
721256352025424
oct3064654477777
9671382635204
10213250113535
1182491147658
12353b5046627
1317156473144
14a46db55d4b
15583182dc5a
hex31a6b27fff

213250113535 has 8 divisors (see below), whose sum is σ = 255984805440. Its totient is φ = 170543644704.

The previous prime is 213250113533. The next prime is 213250113547. The reversal of 213250113535 is 535311052312.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 213250113535 - 21 = 213250113533 is a prime.

It is a super-2 number, since 2×2132501135352 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 213250113497 and 213250113506.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (213250113533) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7039140 + ... + 7069369.

It is an arithmetic number, because the mean of its divisors is an integer number (31998100680).

Almost surely, 2213250113535 is an apocalyptic number.

213250113535 is a deficient number, since it is larger than the sum of its proper divisors (42734691905).

213250113535 is a wasteful number, since it uses less digits than its factorization.

213250113535 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14111537.

The product of its (nonzero) digits is 13500, while the sum is 31.

Adding to 213250113535 its reverse (535311052312), we get a palindrome (748561165847).

The spelling of 213250113535 in words is "two hundred thirteen billion, two hundred fifty million, one hundred thirteen thousand, five hundred thirty-five".

Divisors: 1 5 3023 15115 14108509 70542545 42650022707 213250113535