Base | Representation |
---|---|
bin | 1100011010101001011… |
… | …0000110111111100010 |
3 | 202101121000212210202112 |
4 | 3012222112012333202 |
5 | 11443330144220114 |
6 | 241554401515322 |
7 | 21261024206141 |
oct | 3065226067742 |
9 | 671530783675 |
10 | 213311320034 |
11 | 82512751a3a |
12 | 35411642b42 |
13 | 171660532c7 |
14 | a477d29758 |
15 | 5836dbe13e |
hex | 31aa586fe2 |
213311320034 has 8 divisors (see below), whose sum is σ = 320163645648. Its totient is φ = 106590104820.
The previous prime is 213311320031. The next prime is 213311320091. The reversal of 213311320034 is 430023113312.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×2133113200342 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 213311319991 and 213311320009.
It is not an unprimeable number, because it can be changed into a prime (213311320031) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32773532 + ... + 32780039.
It is an arithmetic number, because the mean of its divisors is an integer number (40020455706).
Almost surely, 2213311320034 is an apocalyptic number.
213311320034 is a deficient number, since it is larger than the sum of its proper divisors (106852325614).
213311320034 is a wasteful number, since it uses less digits than its factorization.
213311320034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65555200.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 213311320034 its reverse (430023113312), we get a palindrome (643334433346).
The spelling of 213311320034 in words is "two hundred thirteen billion, three hundred eleven million, three hundred twenty thousand, thirty-four".
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