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213311320034 = 2162765553571
BaseRepresentation
bin1100011010101001011…
…0000110111111100010
3202101121000212210202112
43012222112012333202
511443330144220114
6241554401515322
721261024206141
oct3065226067742
9671530783675
10213311320034
1182512751a3a
1235411642b42
13171660532c7
14a477d29758
155836dbe13e
hex31aa586fe2

213311320034 has 8 divisors (see below), whose sum is σ = 320163645648. Its totient is φ = 106590104820.

The previous prime is 213311320031. The next prime is 213311320091. The reversal of 213311320034 is 430023113312.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×2133113200342 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 213311319991 and 213311320009.

It is not an unprimeable number, because it can be changed into a prime (213311320031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32773532 + ... + 32780039.

It is an arithmetic number, because the mean of its divisors is an integer number (40020455706).

Almost surely, 2213311320034 is an apocalyptic number.

213311320034 is a deficient number, since it is larger than the sum of its proper divisors (106852325614).

213311320034 is a wasteful number, since it uses less digits than its factorization.

213311320034 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65555200.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 213311320034 its reverse (430023113312), we get a palindrome (643334433346).

The spelling of 213311320034 in words is "two hundred thirteen billion, three hundred eleven million, three hundred twenty thousand, thirty-four".

Divisors: 1 2 1627 3254 65553571 131107142 106655660017 213311320034