Base | Representation |
---|---|
bin | 1100011010101001100… |
… | …1100001000100111111 |
3 | 202101121002120012002212 |
4 | 3012222121201010333 |
5 | 11443330411311221 |
6 | 241554433011035 |
7 | 21261034616351 |
oct | 3065231410477 |
9 | 671532505085 |
10 | 213312213311 |
11 | 8251320208a |
12 | 354119b3a7b |
13 | 171662a6a82 |
14 | a4780bd0d1 |
15 | 5836ee8b5b |
hex | 31aa66113f |
213312213311 has 4 divisors (see below), whose sum is σ = 222586657392. Its totient is φ = 204037769232.
The previous prime is 213312213299. The next prime is 213312213353. The reversal of 213312213311 is 113312213312.
213312213311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-213312213311 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (23), and also a Moran number because the ratio is a prime number: 9274444057 = 213312213311 / (2 + 1 + 3 + 3 + 1 + 2 + 2 + 1 + 3 + 3 + 1 + 1).
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (213312216311) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4637222006 + ... + 4637222051.
It is an arithmetic number, because the mean of its divisors is an integer number (55646664348).
Almost surely, 2213312213311 is an apocalyptic number.
213312213311 is a deficient number, since it is larger than the sum of its proper divisors (9274444081).
213312213311 is an equidigital number, since it uses as much as digits as its factorization.
213312213311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9274444080.
The product of its digits is 648, while the sum is 23.
Adding to 213312213311 its reverse (113312213312), we get a palindrome (326624426623).
Subtracting from 213312213311 its reverse (113312213312), we obtain a palindrome (99999999999).
The spelling of 213312213311 in words is "two hundred thirteen billion, three hundred twelve million, two hundred thirteen thousand, three hundred eleven".
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