Base | Representation |
---|---|
bin | 110000100000001111101101… |
… | …110110101000001110000100 |
3 | 1000222022101201002211121220200 |
4 | 300200033231312220032010 |
5 | 210430032211042224030 |
6 | 2033410500103530500 |
7 | 62635005163234200 |
oct | 6040175566501604 |
9 | 1028271632747820 |
10 | 213322131211140 |
11 | 61a75453854886 |
12 | 1bb13312159a30 |
13 | 9205262b489b3 |
14 | 3a96bbc125b00 |
15 | 199dee8cd0d60 |
hex | c203edda8384 |
213322131211140 has 216 divisors, whose sum is σ = 792339345120960. Its totient is φ = 46193062962816.
The previous prime is 213322131211139. The next prime is 213322131211169. The reversal of 213322131211140 is 41112131223312.
213322131211140 is a `hidden beast` number, since 2 + 1 + 3 + 322 + 1 + 312 + 11 + 14 + 0 = 666.
It is an unprimeable number.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 636310912 + ... + 636646071.
Almost surely, 2213322131211140 is an apocalyptic number.
213322131211140 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
213322131211140 is an abundant number, since it is smaller than the sum of its proper divisors (579017213909820).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
213322131211140 is a wasteful number, since it uses less digits than its factorization.
213322131211140 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1272957031 (or 1272957019 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 27.
Adding to 213322131211140 its reverse (41112131223312), we get a palindrome (254434262434452).
The spelling of 213322131211140 in words is "two hundred thirteen trillion, three hundred twenty-two billion, one hundred thirty-one million, two hundred eleven thousand, one hundred forty".
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