213332044103333 has 4 divisors (see below), whose sum is σ = 220213722945408. Its totient is φ = 206450365261260.

The previous prime is 213332044103329. The next prime is 213332044103363. The reversal of 213332044103333 is 333301440233312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 213332044103333 - 2² = 213332044103329 is a prime.

It is a super-2 number, since 2×213332044103333² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 213332044103293 and 213332044103302.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (213332044103363) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3440839420991 + ... + 3440839421052.

It is an arithmetic number, because the mean of its divisors is an integer number (55053430736352).

Almost surely, 2^{213332044103333} is an apocalyptic number.

It is an amenable number.

213332044103333 is a deficient number, since it is larger than the sum of its proper divisors (6881678842075).

213332044103333 is an equidigital number, since it uses as much as digits as its factorization.

213332044103333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6881678842074.

The product of its (nonzero) digits is 139968, while the sum is 35.

Adding to 213332044103333 its reverse (333301440233312), we get a palindrome (546633484336645).

The spelling of 213332044103333 in words is "two hundred thirteen trillion, three hundred thirty-two billion, forty-four million, one hundred three thousand, three hundred thirty-three".