2134112143331 has 8 divisors (see below), whose sum is σ = 2498472753504. Its totient is φ = 1784623394880.

The previous prime is 2134112143313. The next prime is 2134112143333. The reversal of 2134112143331 is 1333412114312.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2134112143331 is a prime.

It is a super-2 number, since 2×2134112143331² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2134112143294 and 2134112143303.

It is not an unprimeable number, because it can be changed into a prime (2134112143333) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3717965120 + ... + 3717965693.

It is an arithmetic number, because the mean of its divisors is an integer number (312309094188).

Almost surely, 2^{2134112143331} is an apocalyptic number.

2134112143331 is a deficient number, since it is larger than the sum of its proper divisors (364360610173).

2134112143331 is an equidigital number, since it uses as much as digits as its factorization.

2134112143331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7435930861.

The product of its digits is 5184, while the sum is 29.

Adding to 2134112143331 its reverse (1333412114312), we get a palindrome (3467524257643).

The spelling of 2134112143331 in words is "two trillion, one hundred thirty-four billion, one hundred twelve million, one hundred forty-three thousand, three hundred thirty-one".