2134112143333 has 2 divisors, whose sum is σ = 2134112143334. Its totient is φ = 2134112143332.

The previous prime is 2134112143313. The next prime is 2134112143367. The reversal of 2134112143333 is 3333412114312.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1635539169924 + 498572973409 = 1278882^2 + 706097^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2134112143333 is a prime.

It is a super-2 number, since 2×2134112143333² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2134112143295 and 2134112143304.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2134112143313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1067056071666 + 1067056071667.

It is an arithmetic number, because the mean of its divisors is an integer number (1067056071667).

Almost surely, 2^{2134112143333} is an apocalyptic number.

It is an amenable number.

2134112143333 is a deficient number, since it is larger than the sum of its proper divisors (1).

2134112143333 is an equidigital number, since it uses as much as digits as its factorization.

2134112143333 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 15552, while the sum is 31.

Adding to 2134112143333 its reverse (3333412114312), we get a palindrome (5467524257645).

The spelling of 2134112143333 in words is "two trillion, one hundred thirty-four billion, one hundred twelve million, one hundred forty-three thousand, three hundred thirty-three".