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2134132113 = 32113336667
BaseRepresentation
bin111111100110100…
…0100010110010001
312111201202010220010
41333031010112101
513332314211423
6551433505133
7103612552341
oct17715042621
95451663803
102134132113
119a5731053
124b68721a9
132801ab889
14163612d21
15c755a693
hex7f344591

2134132113 has 8 divisors (see below), whose sum is σ = 2846864608. Its totient is φ = 1422077184.

The previous prime is 2134132103. The next prime is 2134132141. The reversal of 2134132113 is 3112314312.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2134132113 - 25 = 2134132081 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 2134132113.

It is not an unprimeable number, because it can be changed into a prime (2134132103) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 161995 + ... + 174672.

It is an arithmetic number, because the mean of its divisors is an integer number (355858076).

Almost surely, 22134132113 is an apocalyptic number.

It is an amenable number.

2134132113 is a deficient number, since it is larger than the sum of its proper divisors (712732495).

2134132113 is a wasteful number, since it uses less digits than its factorization.

2134132113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 338783.

The product of its digits is 432, while the sum is 21.

The square root of 2134132113 is about 46196.6677694398. The cubic root of 2134132113 is about 1287.4798288605.

Adding to 2134132113 its reverse (3112314312), we get a palindrome (5246446425).

The spelling of 2134132113 in words is "two billion, one hundred thirty-four million, one hundred thirty-two thousand, one hundred thirteen".

Divisors: 1 3 2113 6339 336667 1010001 711377371 2134132113