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213414000213 = 371138000071
BaseRepresentation
bin1100011011000001110…
…1110011011001010101
3202101212012002111111010
43012300131303121111
511444032441001323
6242012510402433
721263412033231
oct3066035633125
9671765074433
10213414000213
1182565704097
123543bb00419
13171813c49cb
14a4878175c1
155840e02c93
hex31b0773655

213414000213 has 4 divisors (see below), whose sum is σ = 284552000288. Its totient is φ = 142276000140.

The previous prime is 213414000211. The next prime is 213414000221. The reversal of 213414000213 is 312000414312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 213414000213 - 21 = 213414000211 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 213414000213.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (213414000211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35569000033 + ... + 35569000038.

It is an arithmetic number, because the mean of its divisors is an integer number (71138000072).

Almost surely, 2213414000213 is an apocalyptic number.

It is an amenable number.

213414000213 is a deficient number, since it is larger than the sum of its proper divisors (71138000075).

213414000213 is an equidigital number, since it uses as much as digits as its factorization.

213414000213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 71138000074.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 213414000213 its reverse (312000414312), we get a palindrome (525414414525).

The spelling of 213414000213 in words is "two hundred thirteen billion, four hundred fourteen million, two hundred thirteen", and thus it is an aban number.

Divisors: 1 3 71138000071 213414000213