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2134310433 = 3711436811
BaseRepresentation
bin111111100110110…
…1111111000100001
312111202002012111120
41333031233320201
513332340413213
6551441402453
7103614224253
oct17715577041
95452065446
102134310433
119a5843022
124b6939429
13280241aa8
1416365bcd3
15c7593423
hex7f36fe21

2134310433 has 4 divisors (see below), whose sum is σ = 2845747248. Its totient is φ = 1422873620.

The previous prime is 2134310429. The next prime is 2134310443. The reversal of 2134310433 is 3340134312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2134310433 - 22 = 2134310429 is a prime.

It is not an unprimeable number, because it can be changed into a prime (2134310443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 355718403 + ... + 355718408.

It is an arithmetic number, because the mean of its divisors is an integer number (711436812).

Almost surely, 22134310433 is an apocalyptic number.

It is an amenable number.

2134310433 is a deficient number, since it is larger than the sum of its proper divisors (711436815).

2134310433 is an equidigital number, since it uses as much as digits as its factorization.

2134310433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 711436814.

The product of its (nonzero) digits is 2592, while the sum is 24.

The square root of 2134310433 is about 46198.5977384596. The cubic root of 2134310433 is about 1287.5156868419.

Adding to 2134310433 its reverse (3340134312), we get a palindrome (5474444745).

The spelling of 2134310433 in words is "two billion, one hundred thirty-four million, three hundred ten thousand, four hundred thirty-three".

Divisors: 1 3 711436811 2134310433