Base | Representation |
---|---|
bin | 11111000011101110111… |
… | …111001100111001010001 |
3 | 21120001000222001122220211 |
4 | 133003232333030321101 |
5 | 234432033202332423 |
6 | 4312253501404121 |
7 | 310125162631255 |
oct | 37035677147121 |
9 | 7501028048824 |
10 | 2134313324113 |
11 | 753180259193 |
12 | 2a5789269641 |
13 | 126359c41c99 |
14 | 75430b50265 |
15 | 3a7b985810d |
hex | 1f0eefcce51 |
2134313324113 has 4 divisors (see below), whose sum is σ = 2150605792368. Its totient is φ = 2118020855860.
The previous prime is 2134313324111. The next prime is 2134313324137. The reversal of 2134313324113 is 3114233134312.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2134313324113 - 21 = 2134313324111 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2134313324111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8146233931 + ... + 8146234192.
It is an arithmetic number, because the mean of its divisors is an integer number (537651448092).
Almost surely, 22134313324113 is an apocalyptic number.
It is an amenable number.
2134313324113 is a deficient number, since it is larger than the sum of its proper divisors (16292468255).
2134313324113 is a wasteful number, since it uses less digits than its factorization.
2134313324113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16292468254.
The product of its digits is 15552, while the sum is 31.
Adding to 2134313324113 its reverse (3114233134312), we get a palindrome (5248546458425).
The spelling of 2134313324113 in words is "two trillion, one hundred thirty-four billion, three hundred thirteen million, three hundred twenty-four thousand, one hundred thirteen".
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