Base | Representation |
---|---|
bin | 10011111000001010… |
… | …010010000011001001 |
3 | 2001002110012200210121 |
4 | 103320022102003021 |
5 | 322202342022441 |
6 | 13445513143241 |
7 | 1353623114413 |
oct | 237012220311 |
9 | 61073180717 |
10 | 21343314121 |
11 | 9062820888 |
12 | 41779bab21 |
13 | 2021a99a6c |
14 | 106687d9b3 |
15 | 84db64dd1 |
hex | 4f82920c9 |
21343314121 has 4 divisors (see below), whose sum is σ = 22079290500. Its totient is φ = 20607337744.
The previous prime is 21343314103. The next prime is 21343314151. The reversal of 21343314121 is 12141334312.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 13193738496 + 8149575625 = 114864^2 + 90275^2 .
It is a cyclic number.
It is not a de Polignac number, because 21343314121 - 211 = 21343312073 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (21343314151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 367988146 + ... + 367988203.
It is an arithmetic number, because the mean of its divisors is an integer number (5519822625).
Almost surely, 221343314121 is an apocalyptic number.
It is an amenable number.
21343314121 is a deficient number, since it is larger than the sum of its proper divisors (735976379).
21343314121 is an equidigital number, since it uses as much as digits as its factorization.
21343314121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 735976378.
The product of its digits is 1728, while the sum is 25.
Adding to 21343314121 its reverse (12141334312), we get a palindrome (33484648433).
The spelling of 21343314121 in words is "twenty-one billion, three hundred forty-three million, three hundred fourteen thousand, one hundred twenty-one".
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