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21343314121 = 29735976349
BaseRepresentation
bin10011111000001010…
…010010000011001001
32001002110012200210121
4103320022102003021
5322202342022441
613445513143241
71353623114413
oct237012220311
961073180717
1021343314121
119062820888
1241779bab21
132021a99a6c
14106687d9b3
1584db64dd1
hex4f82920c9

21343314121 has 4 divisors (see below), whose sum is σ = 22079290500. Its totient is φ = 20607337744.

The previous prime is 21343314103. The next prime is 21343314151. The reversal of 21343314121 is 12141334312.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 13193738496 + 8149575625 = 114864^2 + 90275^2 .

It is a cyclic number.

It is not a de Polignac number, because 21343314121 - 211 = 21343312073 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21343314151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 367988146 + ... + 367988203.

It is an arithmetic number, because the mean of its divisors is an integer number (5519822625).

Almost surely, 221343314121 is an apocalyptic number.

It is an amenable number.

21343314121 is a deficient number, since it is larger than the sum of its proper divisors (735976379).

21343314121 is an equidigital number, since it uses as much as digits as its factorization.

21343314121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 735976378.

The product of its digits is 1728, while the sum is 25.

Adding to 21343314121 its reverse (12141334312), we get a palindrome (33484648433).

The spelling of 21343314121 in words is "twenty-one billion, three hundred forty-three million, three hundred fourteen thousand, one hundred twenty-one".

Divisors: 1 29 735976349 21343314121