Base | Representation |
---|---|
bin | 1100011011000110101… |
… | …1010010111001100101 |
3 | 202101220121022120020020 |
4 | 3012301223102321211 |
5 | 11444103141024331 |
6 | 242014514025353 |
7 | 21264046511133 |
oct | 3066153227145 |
9 | 671817276206 |
10 | 213434314341 |
11 | 82576119426 |
12 | 35446878259 |
13 | 171856880c1 |
14 | a48a3c4753 |
15 | 5842ab6c96 |
hex | 31b1ad2e65 |
213434314341 has 4 divisors (see below), whose sum is σ = 284579085792. Its totient is φ = 142289542892.
The previous prime is 213434314321. The next prime is 213434314349. The reversal of 213434314341 is 143413434312.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 213434314341 - 210 = 213434313317 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (213434314349) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35572385721 + ... + 35572385726.
It is an arithmetic number, because the mean of its divisors is an integer number (71144771448).
Almost surely, 2213434314341 is an apocalyptic number.
It is an amenable number.
213434314341 is a deficient number, since it is larger than the sum of its proper divisors (71144771451).
213434314341 is an equidigital number, since it uses as much as digits as its factorization.
213434314341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 71144771450.
The product of its digits is 41472, while the sum is 33.
Adding to 213434314341 its reverse (143413434312), we get a palindrome (356847748653).
The spelling of 213434314341 in words is "two hundred thirteen billion, four hundred thirty-four million, three hundred fourteen thousand, three hundred forty-one".
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