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2134443110673 = 3711481036891
BaseRepresentation
bin11111000011110110101…
…110010011000100010001
321120001101000021111121110
4133003312232103010101
5234432314414020143
64312314415243533
7310131330042606
oct37036656230421
97501330244543
102134443110673
11753237544805
122a58048195a9
1312637aab4573
14754440966ad
153a7c5e43533
hex1f0f6b93111

2134443110673 has 4 divisors (see below), whose sum is σ = 2845924147568. Its totient is φ = 1422962073780.

The previous prime is 2134443110651. The next prime is 2134443110783. The reversal of 2134443110673 is 3760113444312.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 2134443110673 - 28 = 2134443110417 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2134443110603) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 355740518443 + ... + 355740518448.

It is an arithmetic number, because the mean of its divisors is an integer number (711481036892).

Almost surely, 22134443110673 is an apocalyptic number.

It is an amenable number.

2134443110673 is a deficient number, since it is larger than the sum of its proper divisors (711481036895).

2134443110673 is an equidigital number, since it uses as much as digits as its factorization.

2134443110673 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 711481036894.

The product of its (nonzero) digits is 145152, while the sum is 39.

Adding to 2134443110673 its reverse (3760113444312), we get a palindrome (5894556554985).

The spelling of 2134443110673 in words is "two trillion, one hundred thirty-four billion, four hundred forty-three million, one hundred ten thousand, six hundred seventy-three".

Divisors: 1 3 711481036891 2134443110673