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213552015113155 = 597440313433223
BaseRepresentation
bin110000100011100101110100…
…000000000111101111000011
31001000010101002002221211021211
4300203211310000013233003
5210442314011332110110
62034104235201430551
762660424004200025
oct6043456400075703
91030111062854254
10213552015113155
11620539a0272964
121bb4b98993b457
139220b3a471114
143aa3d89070015
1519a4ea0a9998a
hexc23974007bc3

213552015113155 has 8 divisors (see below), whose sum is σ = 258904298735712. Its totient is φ = 169080358357248.

The previous prime is 213552015113131. The next prime is 213552015113189. The reversal of 213552015113155 is 551311510255312.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 213552015113155 - 221 = 213552013016003 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 220156716127 + ... + 220156717096.

It is an arithmetic number, because the mean of its divisors is an integer number (32363037341964).

Almost surely, 2213552015113155 is an apocalyptic number.

213552015113155 is a deficient number, since it is larger than the sum of its proper divisors (45352283622557).

213552015113155 is an equidigital number, since it uses as much as digits as its factorization.

213552015113155 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 440313433325.

The product of its (nonzero) digits is 112500, while the sum is 40.

Adding to 213552015113155 its reverse (551311510255312), we get a palindrome (764863525368467).

The spelling of 213552015113155 in words is "two hundred thirteen trillion, five hundred fifty-two billion, fifteen million, one hundred thirteen thousand, one hundred fifty-five".

Divisors: 1 5 97 485 440313433223 2201567166115 42710403022631 213552015113155