Base | Representation |
---|---|
bin | 11111001000000111000… |
… | …110110010111100001001 |
3 | 21120111011111012122200100 |
4 | 133020013012302330021 |
5 | 240021144302413213 |
6 | 4314352102400013 |
7 | 310352506650063 |
oct | 37100706627411 |
9 | 7514144178610 |
10 | 2139012935433 |
11 | 755172046790 |
12 | 2a667b130009 |
13 | 126928797b9a |
14 | 75758d7a733 |
15 | 3a992225773 |
hex | 1f2071b2f09 |
2139012935433 has 48 divisors (see below), whose sum is σ = 3392186765760. Its totient is φ = 1288065206400.
The previous prime is 2139012935399. The next prime is 2139012935471. The reversal of 2139012935433 is 3345392109312.
2139012935433 is a `hidden beast` number, since 2 + 1 + 3 + 9 + 0 + 12 + 93 + 543 + 3 = 666.
It is not a de Polignac number, because 2139012935433 - 214 = 2139012919049 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2139012935473) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 27690043 + ... + 27767183.
It is an arithmetic number, because the mean of its divisors is an integer number (70670557620).
Almost surely, 22139012935433 is an apocalyptic number.
It is an amenable number.
2139012935433 is a deficient number, since it is larger than the sum of its proper divisors (1253173830327).
2139012935433 is a wasteful number, since it uses less digits than its factorization.
2139012935433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 78950 (or 78947 counting only the distinct ones).
The product of its (nonzero) digits is 524880, while the sum is 45.
The spelling of 2139012935433 in words is "two trillion, one hundred thirty-nine billion, twelve million, nine hundred thirty-five thousand, four hundred thirty-three".
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