Base | Representation |
---|---|
bin | 11111001000100011110… |
… | …010011000101111001101 |
3 | 21120112102000122120222101 |
4 | 133020203302120233031 |
5 | 240023140443440433 |
6 | 4314511532115101 |
7 | 310400441666455 |
oct | 37104362305715 |
9 | 7515360576871 |
10 | 2139494124493 |
11 | 7553997251a0 |
12 | 2a6794305a91 |
13 | 1269a4394b3b |
14 | 757a2c36d65 |
15 | 3a9be5c507d |
hex | 1f223c98bcd |
2139494124493 has 8 divisors (see below), whose sum is σ = 2334188900160. Its totient is φ = 1944831900480.
The previous prime is 2139494124487. The next prime is 2139494124511. The reversal of 2139494124493 is 3944214949312.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 2139494124493 - 217 = 2139493993421 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2139494124403) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8000380 + ... + 8263477.
It is an arithmetic number, because the mean of its divisors is an integer number (291773612520).
Almost surely, 22139494124493 is an apocalyptic number.
It is an amenable number.
2139494124493 is a deficient number, since it is larger than the sum of its proper divisors (194694775667).
2139494124493 is a wasteful number, since it uses less digits than its factorization.
2139494124493 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16275827.
The product of its digits is 6718464, while the sum is 55.
The spelling of 2139494124493 in words is "two trillion, one hundred thirty-nine billion, four hundred ninety-four million, one hundred twenty-four thousand, four hundred ninety-three".
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