21401000113 has 4 divisors (see below), whose sum is σ = 22527368560. Its totient is φ = 20274631668.

The previous prime is 21401000107. The next prime is 21401000143. The reversal of 21401000113 is 31100010412.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-21401000113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 21401000093 and 21401000102.

It is not an unprimeable number, because it can be changed into a prime (21401000143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 563184195 + ... + 563184232.

It is an arithmetic number, because the mean of its divisors is an integer number (5631842140).

Almost surely, 2^21401000113 is an apocalyptic number.

It is an amenable number.

21401000113 is a deficient number, since it is larger than the sum of its proper divisors (1126368447).

21401000113 is a wasteful number, since it uses less digits than its factorization.

21401000113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1126368446.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 21401000113 its reverse (31100010412), we get a palindrome (52501010525).

The spelling of 21401000113 in words is "twenty-one billion, four hundred one million, one hundred thirteen", and thus it is an aban number.