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2140102100121 = 34205931696099
BaseRepresentation
bin11111001001001000000…
…001101000010010011001
321120120222101122221202020
4133021020001220102121
5240030412114200441
64315052131125053
7310421503464246
oct37111001502231
97516871587666
102140102100121
11755680930297
122a6923a43789
13126a70323a2b
147581d8985cd
153aa07b6ae66
hex1f248068499

2140102100121 has 8 divisors (see below), whose sum is σ = 2853477933600. Its totient is φ = 1426730500032.

The previous prime is 2140102100113. The next prime is 2140102100167. The reversal of 2140102100121 is 1210012010412.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2140102100121 - 23 = 2140102100113 is a prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 2140102100121.

It is not an unprimeable number, because it can be changed into a prime (2140102100021) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 413730 + ... + 2109828.

It is an arithmetic number, because the mean of its divisors is an integer number (356684741700).

Almost surely, 22140102100121 is an apocalyptic number.

It is an amenable number.

2140102100121 is a deficient number, since it is larger than the sum of its proper divisors (713375833479).

2140102100121 is a wasteful number, since it uses less digits than its factorization.

2140102100121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2116695.

The product of its (nonzero) digits is 32, while the sum is 15.

Adding to 2140102100121 its reverse (1210012010412), we get a palindrome (3350114110533).

The spelling of 2140102100121 in words is "two trillion, one hundred forty billion, one hundred two million, one hundred thousand, one hundred twenty-one".

Divisors: 1 3 420593 1261779 1696099 5088297 713367366707 2140102100121