2140112432433 has 4 divisors (see below), whose sum is σ = 2853483243248. Its totient is φ = 1426741621620.

The previous prime is 2140112432413. The next prime is 2140112432449. The reversal of 2140112432433 is 3342342110412.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 2140112432433 - 2²⁵ = 2140078878001 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 2140112432433.

It is not an unprimeable number, because it can be changed into a prime (2140112432413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 356685405403 + ... + 356685405408.

It is an arithmetic number, because the mean of its divisors is an integer number (713370810812).

Almost surely, 2^{2140112432433} is an apocalyptic number.

It is an amenable number.

2140112432433 is a deficient number, since it is larger than the sum of its proper divisors (713370810815).

2140112432433 is an equidigital number, since it uses as much as digits as its factorization.

2140112432433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 713370810814.

The product of its (nonzero) digits is 13824, while the sum is 30.

Adding to 2140112432433 its reverse (3342342110412), we get a palindrome (5482454542845).

The spelling of 2140112432433 in words is "two trillion, one hundred forty billion, one hundred twelve million, four hundred thirty-two thousand, four hundred thirty-three".