214011343140221 has 4 divisors (see below), whose sum is σ = 233466919789344. Its totient is φ = 194555766491100.

The previous prime is 214011343140209. The next prime is 214011343140227. The reversal of 214011343140221 is 122041343110412.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-214011343140221 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (214011343140227) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9727788324545 + ... + 9727788324566.

It is an arithmetic number, because the mean of its divisors is an integer number (58366729947336).

Almost surely, 2^{214011343140221} is an apocalyptic number.

It is an amenable number.

214011343140221 is a deficient number, since it is larger than the sum of its proper divisors (19455576649123).

214011343140221 is a wasteful number, since it uses less digits than its factorization.

214011343140221 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19455576649122.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 214011343140221 its reverse (122041343110412), we get a palindrome (336052686250633).

The spelling of 214011343140221 in words is "two hundred fourteen trillion, eleven billion, three hundred forty-three million, one hundred forty thousand, two hundred twenty-one".