Base | Representation |
---|---|
bin | 11111001001001000101… |
… | …101010010000110000011 |
3 | 21120121000012012100012010 |
4 | 133021020231102012003 |
5 | 240030423031343210 |
6 | 4315053220304003 |
7 | 310422002655111 |
oct | 37111055220603 |
9 | 7517005170163 |
10 | 2140113543555 |
11 | 755687336979 |
12 | 2a6927842003 |
13 | 126a727cc5b0 |
14 | 758211d6ab1 |
15 | 3aa08b7b920 |
hex | 1f248b52183 |
2140113543555 has 32 divisors (see below), whose sum is σ = 3687899342400. Its totient is φ = 1053503193600.
The previous prime is 2140113543527. The next prime is 2140113543569. The reversal of 2140113543555 is 5553453110412.
It is not a de Polignac number, because 2140113543555 - 28 = 2140113543299 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (39).
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1812721 + ... + 2750669.
It is an arithmetic number, because the mean of its divisors is an integer number (115246854450).
Almost surely, 22140113543555 is an apocalyptic number.
2140113543555 is a deficient number, since it is larger than the sum of its proper divisors (1547785798845).
2140113543555 is a wasteful number, since it uses less digits than its factorization.
2140113543555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 949671.
The product of its (nonzero) digits is 180000, while the sum is 39.
Adding to 2140113543555 its reverse (5553453110412), we get a palindrome (7693566653967).
The spelling of 2140113543555 in words is "two trillion, one hundred forty billion, one hundred thirteen million, five hundred forty-three thousand, five hundred fifty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.097 sec. • engine limits •