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2140113543555 = 351311701937949
BaseRepresentation
bin11111001001001000101…
…101010010000110000011
321120121000012012100012010
4133021020231102012003
5240030423031343210
64315053220304003
7310422002655111
oct37111055220603
97517005170163
102140113543555
11755687336979
122a6927842003
13126a727cc5b0
14758211d6ab1
153aa08b7b920
hex1f248b52183

2140113543555 has 32 divisors (see below), whose sum is σ = 3687899342400. Its totient is φ = 1053503193600.

The previous prime is 2140113543527. The next prime is 2140113543569. The reversal of 2140113543555 is 5553453110412.

It is not a de Polignac number, because 2140113543555 - 28 = 2140113543299 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (39).

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1812721 + ... + 2750669.

It is an arithmetic number, because the mean of its divisors is an integer number (115246854450).

Almost surely, 22140113543555 is an apocalyptic number.

2140113543555 is a deficient number, since it is larger than the sum of its proper divisors (1547785798845).

2140113543555 is a wasteful number, since it uses less digits than its factorization.

2140113543555 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 949671.

The product of its (nonzero) digits is 180000, while the sum is 39.

Adding to 2140113543555 its reverse (5553453110412), we get a palindrome (7693566653967).

The spelling of 2140113543555 in words is "two trillion, one hundred forty billion, one hundred thirteen million, five hundred forty-three thousand, five hundred fifty-five".

Divisors: 1 3 5 13 15 39 65 195 11701 35103 58505 152113 175515 456339 760565 937949 2281695 2813847 4689745 12193337 14069235 36580011 60966685 182900055 10974941249 32924823747 54874706245 142674236237 164624118735 428022708711 713371181185 2140113543555