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21402002131 = 47944680589
BaseRepresentation
bin10011111011101010…
…001010001011010011
32001020112122100121121
4103323222022023103
5322312403032011
613455411103111
71355235005446
oct237352121323
961215570547
1021402002131
119092965a74
1241935a1a97
132030ca77b3
14107059965d
15853da8e71
hex4fba8a2d3

21402002131 has 4 divisors (see below), whose sum is σ = 21446683200. Its totient is φ = 21357321064.

The previous prime is 21402002123. The next prime is 21402002189. The reversal of 21402002131 is 13120020412.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 21402002131 - 23 = 21402002123 is a prime.

It is a super-2 number, since 2×214020021312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21402002231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22339816 + ... + 22340773.

It is an arithmetic number, because the mean of its divisors is an integer number (5361670800).

Almost surely, 221402002131 is an apocalyptic number.

21402002131 is a deficient number, since it is larger than the sum of its proper divisors (44681069).

21402002131 is an equidigital number, since it uses as much as digits as its factorization.

21402002131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44681068.

The product of its (nonzero) digits is 96, while the sum is 16.

Adding to 21402002131 its reverse (13120020412), we get a palindrome (34522022543).

The spelling of 21402002131 in words is "twenty-one billion, four hundred two million, two thousand, one hundred thirty-one".

Divisors: 1 479 44680589 21402002131