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21402013133 = 174312920979
BaseRepresentation
bin10011111011101010…
…001100110111001101
32001020112122220201002
4103323222030313031
5322312403410013
613455411230045
71355235052514
oct237352146715
961215586632
1021402013133
119092973266
1241935a8325
132030cac7c7
14107059d67b
15853dac358
hex4fba8cdcd

21402013133 has 8 divisors (see below), whose sum is σ = 22713540480. Its totient is φ = 20096328640.

The previous prime is 21402013111. The next prime is 21402013147. The reversal of 21402013133 is 33131020412.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 21402013133 - 26 = 21402013069 is a prime.

It is a super-2 number, since 2×214020131332 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21402013163) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1453163 + ... + 1467816.

It is an arithmetic number, because the mean of its divisors is an integer number (2839192560).

Almost surely, 221402013133 is an apocalyptic number.

It is an amenable number.

21402013133 is a deficient number, since it is larger than the sum of its proper divisors (1311527347).

21402013133 is a wasteful number, since it uses less digits than its factorization.

21402013133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2921427.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 21402013133 its reverse (33131020412), we get a palindrome (54533033545).

The spelling of 21402013133 in words is "twenty-one billion, four hundred two million, thirteen thousand, one hundred thirty-three".

Divisors: 1 17 431 7327 2920979 49656643 1258941949 21402013133