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214020444441 = 371340148147
BaseRepresentation
bin1100011101010010011…
…1001101000100011001
3202110102110020001120110
43013110213031010121
512001303213210231
6242153012514533
721314424522216
oct3072447150431
9673373201513
10214020444441
1182846a63671
123558b01ba49
1317249c3884b
14a50419ab0d
155879295046
hex31d49cd119

214020444441 has 4 divisors (see below), whose sum is σ = 285360592592. Its totient is φ = 142680296292.

The previous prime is 214020444431. The next prime is 214020444467. The reversal of 214020444441 is 144444020412.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 214020444441 - 211 = 214020442393 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 214020444399 and 214020444408.

It is not an unprimeable number, because it can be changed into a prime (214020444431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35670074071 + ... + 35670074076.

It is an arithmetic number, because the mean of its divisors is an integer number (71340148148).

Almost surely, 2214020444441 is an apocalyptic number.

It is an amenable number.

214020444441 is a deficient number, since it is larger than the sum of its proper divisors (71340148151).

214020444441 is an equidigital number, since it uses as much as digits as its factorization.

214020444441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 71340148150.

The product of its (nonzero) digits is 16384, while the sum is 30.

Adding to 214020444441 its reverse (144444020412), we get a palindrome (358464464853).

The spelling of 214020444441 in words is "two hundred fourteen billion, twenty million, four hundred forty-four thousand, four hundred forty-one".

Divisors: 1 3 71340148147 214020444441