Base | Representation |
---|---|
bin | 11111001001001111000… |
… | …011111000011110000011 |
3 | 21120121021121202112221210 |
4 | 133021033003320132003 |
5 | 240031132323144303 |
6 | 4315111545021203 |
7 | 310424435645220 |
oct | 37111703703603 |
9 | 7517247675853 |
10 | 2140220131203 |
11 | 755731517840 |
12 | 2a6957484803 |
13 | 126a8b90b6cb |
14 | 75831420947 |
15 | 3aa131d3203 |
hex | 1f24f0f8783 |
2140220131203 has 64 divisors (see below), whose sum is σ = 3584567992320. Its totient is φ = 1103441184000.
The previous prime is 2140220131199. The next prime is 2140220131223. The reversal of 2140220131203 is 3021310220412.
It is not a de Polignac number, because 2140220131203 - 22 = 2140220131199 is a prime.
It is a super-3 number, since 3×21402201312033 (a number of 38 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a self number, because there is not a number n which added to its sum of digits gives 2140220131203.
It is not an unprimeable number, because it can be changed into a prime (2140220131223) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 39353476 + ... + 39407822.
It is an arithmetic number, because the mean of its divisors is an integer number (56008874880).
Almost surely, 22140220131203 is an apocalyptic number.
2140220131203 is a deficient number, since it is larger than the sum of its proper divisors (1444347861117).
2140220131203 is a wasteful number, since it uses less digits than its factorization.
2140220131203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55648.
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 2140220131203 its reverse (3021310220412), we get a palindrome (5161530351615).
The spelling of 2140220131203 in words is "two trillion, one hundred forty billion, two hundred twenty million, one hundred thirty-one thousand, two hundred three".
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