214033115131 has 8 divisors (see below), whose sum is σ = 247225416624. Its totient is φ = 183129937920.

The previous prime is 214033115123. The next prime is 214033115141. The reversal of 214033115131 is 131511330412.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 214033115131 - 2³ = 214033115123 is a prime.

It is a super-2 number, since 2×214033115131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 214033115096 and 214033115105.

It is not an unprimeable number, because it can be changed into a prime (214033115111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 572280870 + ... + 572281243.

It is an arithmetic number, because the mean of its divisors is an integer number (30903177078).

Almost surely, 2^214033115131 is an apocalyptic number.

214033115131 is a deficient number, since it is larger than the sum of its proper divisors (33192301493).

214033115131 is a wasteful number, since it uses less digits than its factorization.

214033115131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1144562141.

The product of its (nonzero) digits is 1080, while the sum is 25.

Adding to 214033115131 its reverse (131511330412), we get a palindrome (345544445543).

The spelling of 214033115131 in words is "two hundred fourteen billion, thirty-three million, one hundred fifteen thousand, one hundred thirty-one".