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214034331403 = 972206539499
BaseRepresentation
bin1100011101010101110…
…0001011011100001011
3202110110102100120220101
43013111130023130023
512001320242101103
6242154230310231
721314653541044
oct3072534133413
9673412316811
10214034331403
11828538890a2
12355937b8377
131724ca8b699
14a505d738cb
15587a5d9a1d
hex31d570b70b

214034331403 has 4 divisors (see below), whose sum is σ = 216240871000. Its totient is φ = 211827791808.

The previous prime is 214034331397. The next prime is 214034331443. The reversal of 214034331403 is 304133430412.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-214034331403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (214034331443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1103269653 + ... + 1103269846.

It is an arithmetic number, because the mean of its divisors is an integer number (54060217750).

Almost surely, 2214034331403 is an apocalyptic number.

214034331403 is a deficient number, since it is larger than the sum of its proper divisors (2206539597).

214034331403 is an equidigital number, since it uses as much as digits as its factorization.

214034331403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2206539596.

The product of its (nonzero) digits is 10368, while the sum is 28.

Adding to 214034331403 its reverse (304133430412), we get a palindrome (518167761815).

Subtracting 214034331403 from its reverse (304133430412), we obtain a palindrome (90099099009).

The spelling of 214034331403 in words is "two hundred fourteen billion, thirty-four million, three hundred thirty-one thousand, four hundred three".

Divisors: 1 97 2206539499 214034331403