214042130311 has 4 divisors (see below), whose sum is σ = 214075987992. Its totient is φ = 214008272632.

The previous prime is 214042130293. The next prime is 214042130327. The reversal of 214042130311 is 113031240412.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 214042130311 - 2¹⁵ = 214042097543 is a prime.

It is a super-2 number, since 2×214042130311² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (214042130411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16919356 + ... + 16932001.

It is an arithmetic number, because the mean of its divisors is an integer number (53518996998).

Almost surely, 2^214042130311 is an apocalyptic number.

214042130311 is a deficient number, since it is larger than the sum of its proper divisors (33857681).

214042130311 is an equidigital number, since it uses as much as digits as its factorization.

214042130311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33857680.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 214042130311 its reverse (113031240412), we get a palindrome (327073370723).

The spelling of 214042130311 in words is "two hundred fourteen billion, forty-two million, one hundred thirty thousand, three hundred eleven".