Base | Representation |
---|---|
bin | 110000101010110000001000… |
… | …011010001101101110001111 |
3 | 1001001212102022112021221201210 |
4 | 300222300020122031232033 |
5 | 211023344340100100020 |
6 | 2035122303314305503 |
7 | 63041115052312641 |
oct | 6052601032155617 |
9 | 1031772275257653 |
10 | 214044131253135 |
11 | 62223673a78667 |
12 | 2000b22a588293 |
13 | 9258376150a61 |
14 | 3abdb111bc891 |
15 | 19b2ba44c43e0 |
hex | c2ac0868db8f |
214044131253135 has 16 divisors (see below), whose sum is σ = 351726572438496. Its totient is φ = 111071549190528.
The previous prime is 214044131253101. The next prime is 214044131253217. The reversal of 214044131253135 is 531352131440412.
It is not a de Polignac number, because 214044131253135 - 232 = 214039836285839 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 214044131253093 and 214044131253102.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 192832550124 + ... + 192832551233.
It is an arithmetic number, because the mean of its divisors is an integer number (21982910777406).
Almost surely, 2214044131253135 is an apocalyptic number.
214044131253135 is a deficient number, since it is larger than the sum of its proper divisors (137682441185361).
214044131253135 is a wasteful number, since it uses less digits than its factorization.
214044131253135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 385665101402.
The product of its (nonzero) digits is 172800, while the sum is 39.
Adding to 214044131253135 its reverse (531352131440412), we get a palindrome (745396262693547).
The spelling of 214044131253135 in words is "two hundred fourteen trillion, forty-four billion, one hundred thirty-one million, two hundred fifty-three thousand, one hundred thirty-five".
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