Base | Representation |
---|---|
bin | 11111001001011100011… |
… | …000001000100011011011 |
3 | 21120121212012011002101100 |
4 | 133021130120020203123 |
5 | 240032112021400041 |
6 | 4315150045322443 |
7 | 310433120633631 |
oct | 37113430104333 |
9 | 7517765132340 |
10 | 2140443543771 |
11 | 755836640a25 |
12 | 2a69ba266423 |
13 | 126ac5ca24b0 |
14 | 75852d79351 |
15 | 3aa27b146b6 |
hex | 1f25c6088db |
2140443543771 has 48 divisors (see below), whose sum is σ = 3346171395840. Its totient is φ = 1310642424000.
The previous prime is 2140443543761. The next prime is 2140443543787. The reversal of 2140443543771 is 1773453440412.
2140443543771 is a `hidden beast` number, since 2 + 140 + 4 + 4 + 3 + 5 + 437 + 71 = 666.
It is not a de Polignac number, because 2140443543771 - 225 = 2140409989339 is a prime.
It is a super-3 number, since 3×21404435437713 (a number of 38 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (2140443543761) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 29889210 + ... + 29960736.
It is an arithmetic number, because the mean of its divisors is an integer number (69711904080).
Almost surely, 22140443543771 is an apocalyptic number.
2140443543771 is a deficient number, since it is larger than the sum of its proper divisors (1205727852069).
2140443543771 is a wasteful number, since it uses less digits than its factorization.
2140443543771 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 72816 (or 72813 counting only the distinct ones).
The product of its (nonzero) digits is 1128960, while the sum is 45.
The spelling of 2140443543771 in words is "two trillion, one hundred forty billion, four hundred forty-three million, five hundred forty-three thousand, seven hundred seventy-one".
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