Base | Representation |
---|---|
bin | 1001101110111101001100… |
… | …00001001000011000111111 |
3 | 2210210021000212222221121121 |
4 | 10313132212001020120333 |
5 | 10301143113440202320 |
6 | 113305050232211411 |
7 | 4336301060350126 |
oct | 467364601103077 |
9 | 83707025887547 |
10 | 21404607350335 |
11 | 6902708917880 |
12 | 2498433839b67 |
13 | bc35a45ac6c1 |
14 | 53ddba718abd |
15 | 271bb273b8aa |
hex | 1377a604863f |
21404607350335 has 16 divisors (see below), whose sum is σ = 28028884453920. Its totient is φ = 15562371853440.
The previous prime is 21404607350303. The next prime is 21404607350353. The reversal of 21404607350335 is 53305370640412.
It is not a de Polignac number, because 21404607350335 - 25 = 21404607350303 is a prime.
It is a super-2 number, since 2×214046073503352 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 21404607350291 and 21404607350300.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 57504180 + ... + 57875209.
It is an arithmetic number, because the mean of its divisors is an integer number (1751805278370).
Almost surely, 221404607350335 is an apocalyptic number.
21404607350335 is a deficient number, since it is larger than the sum of its proper divisors (6624277103585).
21404607350335 is a wasteful number, since it uses less digits than its factorization.
21404607350335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 115382778.
The product of its (nonzero) digits is 907200, while the sum is 43.
Adding to 21404607350335 its reverse (53305370640412), we get a palindrome (74709977990747).
The spelling of 21404607350335 in words is "twenty-one trillion, four hundred four billion, six hundred seven million, three hundred fifty thousand, three hundred thirty-five".
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