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21406489597 = 23930716939
BaseRepresentation
bin10011111011111011…
…010001101111111101
32001020212002100021001
4103323323101233331
5322320030131342
613500051210301
71355321105443
oct237373215775
961225070231
1021406489597
119095450519
124194ba6991
132031bb91bc
141071006b93
158544938b7
hex4fbed1bfd

21406489597 has 4 divisors (see below), whose sum is σ = 22337206560. Its totient is φ = 20475772636.

The previous prime is 21406489583. The next prime is 21406489609. The reversal of 21406489597 is 79598460412.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21406489597 - 27 = 21406489469 is a prime.

It is a super-3 number, since 3×214064895973 (a number of 32 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21406489547) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 465358447 + ... + 465358492.

It is an arithmetic number, because the mean of its divisors is an integer number (5584301640).

Almost surely, 221406489597 is an apocalyptic number.

It is an amenable number.

21406489597 is a deficient number, since it is larger than the sum of its proper divisors (930716963).

21406489597 is an equidigital number, since it uses as much as digits as its factorization.

21406489597 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 930716962.

The product of its (nonzero) digits is 4354560, while the sum is 55.

The spelling of 21406489597 in words is "twenty-one billion, four hundred six million, four hundred eighty-nine thousand, five hundred ninety-seven".

Divisors: 1 23 930716939 21406489597