Base | Representation |
---|---|
bin | 11111001001101110111… |
… | …100110111100010000011 |
3 | 21120122122220111222222011 |
4 | 133021232330313202003 |
5 | 240033231310211032 |
6 | 4315241020353351 |
7 | 310443623436400 |
oct | 37115674674203 |
9 | 7518586458864 |
10 | 2140755163267 |
11 | 7559865312a6 |
12 | 2a6a866a5857 |
13 | 126b4570b026 |
14 | 758824d52a7 |
15 | 3aa4516b247 |
hex | 1f26ef37883 |
2140755163267 has 24 divisors (see below), whose sum is σ = 2527633941840. Its totient is φ = 1807403209920.
The previous prime is 2140755163243. The next prime is 2140755163303. The reversal of 2140755163267 is 7623615570412.
It is a de Polignac number, because none of the positive numbers 2k-2140755163267 is a prime.
It is a super-2 number, since 2×21407551632672 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (49).
It is a self number, because there is not a number n which added to its sum of digits gives 2140755163267.
It is not an unprimeable number, because it can be changed into a prime (2140755163667) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 73751217 + ... + 73780237.
It is an arithmetic number, because the mean of its divisors is an integer number (105318080910).
Almost surely, 22140755163267 is an apocalyptic number.
2140755163267 is a deficient number, since it is larger than the sum of its proper divisors (386878778573).
2140755163267 is a wasteful number, since it uses less digits than its factorization.
2140755163267 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51571 (or 51564 counting only the distinct ones).
The product of its (nonzero) digits is 2116800, while the sum is 49.
The spelling of 2140755163267 in words is "two trillion, one hundred forty billion, seven hundred fifty-five million, one hundred sixty-three thousand, two hundred sixty-seven".
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